Find the number of ways of arranging the letters of the word 'INDEPENDENCE'.

Question

Accepted Answer

The word 'INDEPENDENCE' contains 12 letters where 'N' appears 3 times, 'D' appears 2 times, 'E' appears 4 times, and others are distinct. Total arrangements = $\frac{12!}{3! 2! 4!} = \frac{479001600}{6 	imes 2 	imes 24} = \frac{479001600}{288} = 1663200$. Thus, option B is correct.

Permutations and Combinations

❓ Sibling Questions in this Chapter