Evaluate $^5P2$.

Question

Evaluate $^5P2$.

Accepted Answer

The formula for permutation is $^nPr = \frac{n!}{(n-r)!}$. Substituting $n = 5$ and $r = 2$, we get $^5P2 = \frac{5!}{(5-2)!} = \frac{5!}{3!} = \frac{5 	imes 4 	imes 3!}{3!} = 5 	imes 4 = 20$. Therefore, option A is correct.

Permutations and Combinations

❓ Sibling Questions in this Chapter