A committee of 3 persons is to be constituted from a group of 2 men and 3 women. In how many ways can this be done?
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Question

A committee of 3 persons is to be constituted from a group of 2 men and 3 women. In how many ways can this be done?

Accepted Answer

Total persons = 5. We need to select 3 persons out of 5. The number of ways is $^{5}C{3} = \frac{5!}{3!2!} = \frac{5 	imes 4}{2 	imes 1} = 10$. Thus, option C is correct.

Permutations and Combinations

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