If $\frac{1}{6!} + \frac{1}{7!} = \frac{x}{8!}$, find the value of $x$.

Question

Accepted Answer

Multiply the entire equation by $8!$: $\frac{8!}{6!} + \frac{8!}{7!} = x \implies 8 	imes 7 + 8 = x \implies 56 + 8 = x \implies x = 64$. Thus, option B is correct.

Permutations and Combinations

❓ Sibling Questions in this Chapter