How many 3-digit numbers can be formed using the digits 1, 2, 3, 4, 5 without repetition?
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Question

How many 3-digit numbers can be formed using the digits 1, 2, 3, 4, 5 without repetition?

Accepted Answer

The number of 3-digit numbers formed from 5 distinct digits without repetition is given by $^{5}P{3} = \frac{5!}{(5-3)!} = \frac{5!}{2!} = 5 	imes 4 	imes 3 = 60$. Thus, option B is correct.

Permutations and Combinations

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