What is the value of $^{5}P{2}$?

Question

Accepted Answer

The formula for permutation is $^{n}P{r} = \frac{n!}{(n-r)!}$. Substituting $n = 5$ and $r = 2$, we get $^{5}P{2} = \frac{5!}{(5-2)!} = \frac{5!}{3!} = \frac{5 	imes 4 	imes 3!}{3!} = 5 	imes 4 = 20$. Thus, option C is correct.

Permutations and Combinations

❓ Sibling Questions in this Chapter