If $^nC{12} = ^nC8$, find the value of $^nC2$.

Question

Accepted Answer

Since $^nC{12} = ^nC8$, we have $n = 12 + 8 = 20$. Now we need to find $^20C2 = \frac{20 	imes 19}{2 	imes 1} = 190$. Therefore, option D is correct.

Permutations and Combinations