What is the nature of the roots of the quadratic equation $2x^2 - 4x + 3 = 0$?

Question

Accepted Answer

For the given quadratic equation $2x^2 - 4x + 3 = 0$: 
Comparing with the standard form $ax^2 + bx + c = 0$: $a = 2$ $b = -4$ $c = 3$ 
The discriminant ($D$) is given by: $$D = b^2 - 4ac$$ $$D = (-4)^2 - 4(2)(3)$$ $$D = 16 - 24 = -8$$ 
Since $D

Quadratic Equations

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