Quadratic Equations

Which of the following is a quadratic equation?

The degree of a quadratic equation is always:

For the quadratic equation $ax^2 + bx + c = 0$, the discriminant $D$ is given by:

If the discriminant $D = 0$, then the roots of the quadratic equation are:

The discriminant of the quadratic equation $2x^2 - 4x + 3 = 0$ is:

The roots of the equation $x^2 - 9 = 0$ are:

A quadratic equation $ax^2 + bx + c = 0$ has two distinct real roots if:

If the equation $x^2 - kx + 4 = 0$ has equal roots, then the value of $k$ is:

The sum of the roots of the quadratic equation $x^2 - 5x + 6 = 0$ is:

The product of the roots of the quadratic equation $3x^2 + 11x - 4 = 0$ is:

The quadratic formula to find the roots of $ax^2 + bx + c = 0$ is:

The maximum number of real roots a quadratic equation can have is:

The nature of the roots of the quadratic equation $x^2 + x + 1 = 0$ is:

The roots of the quadratic equation $2x^2 - 5x + 3 = 0$ are:

If $x = 2$ is a root of the equation $kx^2 + 2x - 3 = 0$, then the value of $k$ is:

A quadratic equation whose roots are 2 and 3 is:

What is the discriminant of the quadratic equation $(x - 1)(x + 2) = 0$?

The roots of the quadratic equation $(x - 3)^2 = 0$ are:

The standard form of a quadratic equation in variable $x$ is:

The value of the discriminant for $x^2 - 4x + 4 = 0$ is:

If the quadratic equation $kx^2 - 6x + 9 = 0$ has equal real roots, then the value of $k$ is:

For what value of $k$ does the quadratic equation $x^2 - kx + 9 = 0$ have equal real roots?

What is the nature of the roots of the quadratic equation $2x^2 - 4x + 3 = 0$?