CBSE · Class 12 · Physics · Electric Charges and FieldsThe electric field intensity $E$ at a perpendicular distance $r$ from an infinitely long straight uniformly charged wire depends on $r$ as:
According to Gauss's Law, the electric field intensity $E$ due to an infinitely long straight wire carrying a uniform linear charge density $\lambda$ at a perpendicular distance $r$ is given by the formula:
$$E = \frac{\lambda}{2\pi\epsilon_0 r}$$ \nFrom the above relation, it is clear that $E$ is inversely proportional to $r$, i.e., $E \propto \frac{1}{r}$. \nTherefore, the correct option is $E \propto \frac{1}{r}$.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electric Charges and Fields.
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electric Charges and Fields.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electric Charges and Fields.