CBSE · Class 12 · Physics · Electric Charges and FieldsTwo point charges separated by a distance $r$ exert a force $F$ on each other in vacuum. If they are placed in a medium of dielectric constant $K = 4$ at the same distance, the new electrostatic force will be:
Step-by-Step Solution
The electrostatic force in a medium of dielectric constant $K$ is given by $F' = \frac{F}{K}$.\nSince $K = 4$, the new force is $F' = \frac{F}{4}$.
Detailed Options Breakdown
Option : $F/4$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: $4F$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electric Charges and Fields.
Option 2: $F/2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electric Charges and Fields.
Option 3: $16F$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electric Charges and Fields.
💡 Study Guide: This question tests core syllabus concepts from Electric Charges and Fields. For formulas, key summaries, and mock exam reference guides, read the full Electric Charges and Fields Revision Notes.