CBSE · Class 12 · Physics · Electric Charges and FieldsThe number of electrons present in $1\text{ Coulomb}$ of negative charge is:
Step-by-Step Solution
Using the quantization formula $q = n e$: $$n = \frac{q}{e} = \frac{1\text{ C}}{1.6 \times 10^{-19}\text{ C}} = 6.25 \times 10^{18}$$
Detailed Options Breakdown
Option : $6.25 \times 10^{18}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: $1.6 \times 10^{-19}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electric Charges and Fields.
Option 2: $6.25 \times 10^{19}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electric Charges and Fields.
Option 3: $1.6 \times 10^{19}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Electric Charges and Fields.
💡 Study Guide: This question tests core syllabus concepts from Electric Charges and Fields. For formulas, key summaries, and mock exam reference guides, read the full Electric Charges and Fields Revision Notes.