NCERT · Class 9 · Mathematics · Heron's FormulaWhat is the area of an isosceles right triangle with equal sides of length $a$?
Step-by-Step Solution
For an isosceles right triangle with base $a$ and height $a$, the area is $\frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2}a^2$.
Detailed Options Breakdown
Option : $a^2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Heron's Formula.
Option 1: $\frac{1}{2}a^2$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: $\frac{\sqrt{3}}{4}a^2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Heron's Formula.
Option 3: $\sqrt{2}a^2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Heron's Formula.
💡 Study Guide: This question tests core syllabus concepts from Heron's Formula. For formulas, key summaries, and mock exam reference guides, read the full Heron's Formula Revision Notes.