NCERT · Class 9 · Mathematics · Heron's FormulaFind the area of an equilateral triangle with side $4\text{ cm}$.
Step-by-Step Solution
For an equilateral triangle with side $a = 4$, the area is $\frac{\sqrt{3}}{4}a^2 = \frac{\sqrt{3}}{4}(4)^2 = 4\sqrt{3}\text{ cm}^2$.
Detailed Options Breakdown
Option : $2\sqrt{3}\text{ cm}^2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Heron's Formula.
Option 1: $4\sqrt{3}\text{ cm}^2$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: $8\sqrt{3}\text{ cm}^2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Heron's Formula.
Option 3: $16\sqrt{3}\text{ cm}^2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Heron's Formula.
💡 Study Guide: This question tests core syllabus concepts from Heron's Formula. For formulas, key summaries, and mock exam reference guides, read the full Heron's Formula Revision Notes.