NCERT · Class 8 · Mathematics · Exponents and PowersEvaluate: $\{(1/3)^{-2} - (1/2)^{-3}\} \div (1/4)^{-2}$
Step-by-Step Solution
Calculate each term: $(1/3)^{-2} = 3^2 = 9$, $(1/2)^{-3} = 2^3 = 8$, $(1/4)^{-2} = 4^2 = 16$. Substituting these: $(9 - 8) \div 16 = 1 \div 16 = \frac{1}{16}$.
Detailed Options Breakdown
Option : 1/16 (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: 16
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Exponents and Powers.
Option 2: 1
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Exponents and Powers.
Option 3: -1/16
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Exponents and Powers.
💡 Study Guide: This question tests core syllabus concepts from Exponents and Powers. For formulas, key summaries, and mock exam reference guides, read the full Exponents and Powers Revision Notes.