NCERT · Class 8 · Mathematics · Exponents and PowersWhat is the value of $(3^0 + 4^{-1}) \times 2^2$?
Step-by-Step Solution
Using the laws of exponents, $3^0 = 1$ and $4^{-1} = \frac{1}{4}$. So, $(3^0 + 4^{-1}) = (1 + \frac{1}{4}) = \frac{5}{4}$. Multiplying by $2^2$ (which is 4): $\frac{5}{4} \times 4 = 5$.
Detailed Options Breakdown
Option : 1
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Exponents and Powers.
Option 1: 5 (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: 4
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Exponents and Powers.
Option 3: 7/4
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Exponents and Powers.
💡 Study Guide: This question tests core syllabus concepts from Exponents and Powers. For formulas, key summaries, and mock exam reference guides, read the full Exponents and Powers Revision Notes.