NCERT · Class 11 · Physics · OscillationsThe phase difference between displacement and acceleration of a particle in SHM is:
Step-by-Step Solution
Acceleration is given by $a = -\omega^2 x = \omega^2 A \sin(\omega t + \pi)$. Displacement is $x = A \sin(\omega t)$. Thus, phase difference between $x$ and $a$ is $\pi$ radians ($180^\circ$).
Detailed Options Breakdown
Option : 0
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
Option 1: $\frac{\pi}{2}\text{ rad}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
Option 2: $\pi\text{ rad}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 3: $\frac{3\pi}{2}\text{ rad}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
💡 Study Guide: This question tests core syllabus concepts from Oscillations. For formulas, key summaries, and mock exam reference guides, read the full Oscillations Revision Notes.