NCERT · Class 11 · Physics · OscillationsIf the length of a simple pendulum is increased by 4 times, its time period becomes:
Step-by-Step Solution
The time period of a simple pendulum is $T = 2\pi \sqrt{\frac{l}{g}}$. Since $T \propto \sqrt{l}$, if $l$ becomes $4l$, new time period $T' = \sqrt{4} T = 2T$.
Detailed Options Breakdown
Option : Half
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
Option 1: Doubled (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: Four times
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
Option 3: Unchanged
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Oscillations.
💡 Study Guide: This question tests core syllabus concepts from Oscillations. For formulas, key summaries, and mock exam reference guides, read the full Oscillations Revision Notes.