NCERT · Class 11 · Physics · GravitationTotal mechanical energy of a satellite of mass $m$ revolving close to Earth's surface in a circular orbit of radius $R$ is:
Step-by-Step Solution
Kinetic Energy $K = \frac{GMm}{2R}$ and Potential Energy $U = -\frac{GMm}{R}$. Total Energy $E = K + U = -\frac{GMm}{2R}$.
Detailed Options Breakdown
Option : $-\frac{GMm}{2R}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: $\frac{GMm}{2R}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
Option 2: $-\frac{GMm}{R}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
Option 3: Zero
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
💡 Study Guide: This question tests core syllabus concepts from Gravitation. For formulas, key summaries, and mock exam reference guides, read the full Gravitation Revision Notes.