NCERT · Class 11 · Physics · GravitationWhat is the dimensional formula of Universal Gravitational Constant ($G$)?
Step-by-Step Solution
From $F = \frac{G m_1 m_2}{r^2}$, we get $G = \frac{F r^2}{m_1 m_2}$. Substituting dimensions: $[G] = \frac{[M L T^{-2}][L^2]}{[M^2]} = [M^{-1} L^3 T^{-2}]$.
Detailed Options Breakdown
Option : $[M^{-1} L^3 T^{-2}]$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: $[M^1 L^3 T^{-2}]$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
Option 2: $[M^{-1} L^2 T^{-2}]$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
Option 3: $[M^0 L^3 T^{-1}]$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
💡 Study Guide: This question tests core syllabus concepts from Gravitation. For formulas, key summaries, and mock exam reference guides, read the full Gravitation Revision Notes.