NCERT · Class 11 · Physics · GravitationIf Earth stops rotating about its axis, the value of $g$ at the equator will:
Step-by-Step Solution
The value of acceleration due to gravity at latitude $\phi$ is $g' = g - \omega^2 R \cos^2 \phi$. At the equator ($ \phi = 0^\circ$), $g' = g - \omega^2 R$. If $\omega = 0$, $g'$ increases to $g$.
Detailed Options Breakdown
Option : Increase (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: Decrease
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
Option 2: Remain unchanged
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
Option 3: Become zero
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
💡 Study Guide: This question tests core syllabus concepts from Gravitation. For formulas, key summaries, and mock exam reference guides, read the full Gravitation Revision Notes.