NCERT · Class 11 · Physics · GravitationIf a planet has mass twice that of Earth and radius twice that of Earth, the ratio of escape velocity on that planet to that on Earth is:
Step-by-Step Solution
$v_e = \sqrt{\frac{2GM}{R}}$. If $M' = 2M$ and $R' = 2R$, then $v_e' = \sqrt{\frac{2G(2M)}{2R}} = \sqrt{\frac{2GM}{R}} = v_e$. Thus, the ratio is $1:1$.
Detailed Options Breakdown
Option : $1 : 1$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: $1 : 2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
Option 2: $2 : 1$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
Option 3: $1 : \sqrt{2}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
💡 Study Guide: This question tests core syllabus concepts from Gravitation. For formulas, key summaries, and mock exam reference guides, read the full Gravitation Revision Notes.