NCERT · Class 11 · Physics · GravitationAt what depth $d$ below the Earth's surface does acceleration due to gravity become half of its value at the surface ($g/2$)?
Step-by-Step Solution
Variation of $g$ with depth is $g' = g\left(1 - \frac{d}{R}\right)$. Setting $g' = \frac{g}{2}$, we get $1 - \frac{d}{R} = \frac{1}{2} \implies d = \frac{R}{2}$.
Detailed Options Breakdown
Option : $d = R$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
Option 1: $d = \frac{R}{2}$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: $d = \frac{R}{4}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
Option 3: $d = 2R$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Gravitation.
💡 Study Guide: This question tests core syllabus concepts from Gravitation. For formulas, key summaries, and mock exam reference guides, read the full Gravitation Revision Notes.