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NCERT · Class 10 · Mathematics · Introduction to TrigonometryIf $\sin A = \frac{3}{4}$, calculate $\cos A$ and $\tan A$. Show all steps.

Step-by-Step Solution

Given: $\sin A = \frac{3}{4}$ \nWe know that in a right-angled triangle, $\sin A = \frac{\text{Opposite side}}{\text{Hypotenuse}} = \frac{\text{Perpendicular}}{\text{Hypotenuse}}$. \nLet the perpendicular be $3k$ and the hypotenuse be $4k$, where $k$ is a positive real number.\nUsing Pythagoras theorem in right-angled triangle ABC: $(\text{Hypotenuse})^2 = (\text{Base})^2 + (\text{Perpendicular})^2$ $(4k)^2 = (\text{Base})^2 + (3k)^2$ $16k^2 = (\text{Base})^2 + 9k^2$ $(\text{Base})^2 = 16k^2 - 9k^2$ $(\text{Base})^2 = 7k^2$ $\text{Base} = \sqrt{7}k$ \nNow, calculating $\cos A$: $\cos A = \frac{\text{Base}}{\text{Hypotenuse}} = \frac{\sqrt{7}k}{4k} = \frac{\sqrt{7}}{4}$ \nNow, calculating $\tan A$: $\tan A = \frac{\text{Perpendicular}}{\text{Base}} = \frac{3k}{\sqrt{7}k} = \frac{3}{\sqrt{7}}$ \nTherefore, $\cos A = \frac{\sqrt{7}}{4}$ and $\tan A = \frac{3}{\sqrt{7}}$.

💡 Study Guide: This question tests core syllabus concepts from Introduction to Trigonometry. For formulas, key summaries, and mock exam reference guides, read the full Introduction to Trigonometry Revision Notes.
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