NCERT · Class 10 · Mathematics · Introduction to TrigonometryThe value of $9 \sec^2 A - 9 \tan^2 A$ is:
Step-by-Step Solution
Taking 9 as common from the expression, we get $9(\sec^2 A - \tan^2 A)$. We know the fundamental trigonometric identity that $\sec^2 A - \tan^2 A = 1$ for any angle $A$. Substituting this identity gives $9(1) = 9$.
Detailed Options Breakdown
Option : 1
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Introduction to Trigonometry.
Option 1: 9 (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: 8
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Introduction to Trigonometry.
Option 3: 0
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Introduction to Trigonometry.
💡 Study Guide: This question tests core syllabus concepts from Introduction to Trigonometry. For formulas, key summaries, and mock exam reference guides, read the full Introduction to Trigonometry Revision Notes.