NCERT · Class 10 · Mathematics · Applications of TrigonometryThe angle of depression of a car parked on the ground from the top of a 75 m high tower is 30°. The distance of the car from the base of the tower is:
The height of the tower is $75$ m. The angle of depression is equal to the angle of elevation, which is $30^\circ$. Let the distance of the car from the base of the tower be $x$. Then, $\tan 30^\circ = \frac{\text{Height}}{\text{Distance}} = \frac{75}{x}$. Since $\tan 30^\circ = \frac{1}{\sqrt{3}}$, we have $\frac{1}{\sqrt{3}} = \frac{75}{x}$, which gives $x = 75\sqrt{3}$ m.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.