NCERT · Class 10 · Mathematics · Applications of TrigonometryIf the height of a tower and the distance of the point of observation from its foot are both increased by 10%, then the angle of elevation of its top:
Let the original height be $h$ and the original distance be $x$. The angle of elevation $\theta$ is given by $\tan \theta = \frac{h}{x}$. When both height and distance are increased by 10%, the new height is $1.1h$ and the new distance is $1.1x$. The new angle of elevation $\theta'$ is given by $\tan \theta' = \frac{1.1h}{1.1x} = \frac{h}{x} = \tan \theta$. Thus, $\theta' = \theta$. The angle remains unchanged.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.