The distance travelled by a body falling freely from rest in the first, second, and third seconds of its motion are in the ratio:
1 mark
🔍 View Detailed Solution & Schema →

Question

The distance travelled by a body falling freely from rest in the first, second, and third seconds of its motion are in the ratio:

Accepted Answer

Distance travelled in the nth second is given by sn = u + a/2 (2n - 1). For free fall from rest, u = 0, a = g. Thus s1 : s2 : s3 = (2(1)-1) : (2(2)-1) : (2(3)-1) = 1 : 3 : 5.

Motion in a Straight Line

❓ Sibling Questions in this Chapter