According to Stokes' law, the terminal velocity ($v_t$) of a small spherical body falling in a viscous medium is directly proportional to:
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Question

According to Stokes' law, the terminal velocity ($vt$) of a small spherical body falling in a viscous medium is directly proportional to:

Accepted Answer

According to Stokes' law formula $vt = \frac{2}{9}\frac{r^2(\rho - \sigma)g}{\eta}$, the terminal velocity is directly proportional to the square of the radius ($r^2$) of the spherical body.

Mechanical Properties of Fluids

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