If a planet has mass twice that of Earth and radius twice that of Earth, the ratio of escape velocity on that planet to that on Earth is:
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Question

If a planet has mass twice that of Earth and radius twice that of Earth, the ratio of escape velocity on that planet to that on Earth is:

Accepted Answer

$ve = \sqrt{\frac{2GM}{R}}$. If $M' = 2M$ and $R' = 2R$, then $ve' = \sqrt{\frac{2G(2M)}{2R}} = \sqrt{\frac{2GM}{R}} = ve$. Thus, the ratio is $1:1$.

Gravitation