Find the coordinates of the focus of the parabola $y^2 = 12x$.

Question

Accepted Answer

The given equation is $y^2 = 12x$. Comparing this with the standard equation $y^2 = 4ax$, we get $4a = 12$, which gives $a = 3$. The focus of the parabola $y^2 = 4ax$ is given by $(a, 0)$. Therefore, the focus is $(3, 0)$.

Conic Sections

❓ Sibling Questions in this Chapter