What are the roots of the quadratic equation $3x^2 - 4x + \frac{20}{3} = 0$?

Question

Accepted Answer

Multiply by 3: $9x^2 - 12x + 20 = 0$. Using the quadratic formula with $a=9, b=-12, c=20$: $x = \frac{12 \pm \sqrt{(-12)^2 - 4(9)(20)}}{2(9)} = \frac{12 \pm \sqrt{144 - 720}}{18} = \frac{12 \pm \sqrt{-576}}{18} = \frac{12 \pm 24i}{18} = \frac{2 \pm 4i}{3}$.

Complex Numbers and Quadratic Equations

❓ Sibling Questions in this Chapter