If $30 ext{ g}$ of $H2$ reacts with $30 ext{ g}$ of $O2$ to form water ($2H2 + O2 ightarrow 2H2O$), which reactant i

Question

If $30	ext{ g}$ of $H2$ reacts with $30	ext{ g}$ of $O2$ to form water ($2H2 + O2 ightarrow 2H2O$), which reactant is the limiting reagent?

Accepted Answer

Moles of $H2 = \frac{30}{2} = 15	ext{ moles}$. 
Moles of $O2 = \frac{30}{32} = 0.9375	ext{ moles}$. 
Reaction requires $2	ext{ moles of } H2$ for $1	ext{ mole of } O2$. 
For $0.9375	ext{ moles of } O2$, only $1.875	ext{ moles of } H2$ are required. Thus, $O2$ gets completely consumed first, making it the limiting reagent.

Some Basic Concepts of Chemistry

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