If a reaction has $\Delta H = +30.58 ext{ kJ mol}^{-1}$ and $\Delta S = +66.1 ext{ J K}^{-1} ext{mol}^{-1}$, at what

Question

If a reaction has $\Delta H = +30.58	ext{ kJ mol}^{-1}$ and $\Delta S = +66.1	ext{ J K}^{-1}	ext{mol}^{-1}$, at what temperature will the reaction reach equilibrium?

Accepted Answer

At equilibrium, $\Delta G = 0 \implies \Delta H - T\Delta S = 0 \implies T = \frac{\Delta H}{\Delta S}$. Converting $\Delta H$ to J: $T = \frac{30580	ext{ J mol}^{-1}}{66.1	ext{ J K}^{-1}	ext{mol}^{-1}} \approx 462.6	ext{ K}$.

Chemical Thermodynamics

❓ Sibling Questions in this Chapter