Verify that for any two positive integers a and b, HCF(a, b) × LCM(a, b) = a × b, taking a = 6 and b = 20.

Question

Accepted Answer

For numbers 6 and 20, we know that their prime factorizations are 6 = 2 × 3 and 20 = 2² × 5. From this, we find HCF(6, 20) = 2 and LCM(6, 20) = 60. Now, calculating the product of HCF and LCM gives 2 × 60 = 120. Calculating the product of the numbers a and b gives 6 × 20 = 120. Since both products are equal to 120, the relation is verified.

Real Numbers

❓ Sibling Questions in this Chapter