If a pole 6 m high casts a shadow 2√3 m long on the ground, then the sun's elevation is:
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Question

If a pole 6 m high casts a shadow 2√3 m long on the ground, then the sun's elevation is:

Accepted Answer

Let the angle of elevation be $	heta$. Height of the pole = $6$ m, length of shadow = $2\sqrt{3}$ m. $	an 	heta = \frac{6}{2\sqrt{3}} = \frac{3}{\sqrt{3}} = \sqrt{3}$. Since $	an 60^\circ = \sqrt{3}$, we have $	heta = 60^\circ$.

Applications of Trigonometry

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