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MP Board · Class 12 · Physics · Alternating CurrentExplain the concept of 'Wattless Current' in an alternating current (AC) circuit. Under what condition is the current in an AC circuit said to be purely wattless?

Step-by-Step Solution

In an alternating current (AC) circuit, the average power dissipated per cycle is given by the formula: $$P = V_{rms} I_{rms} \cos\phi$$\nwhere $V_{rms}$ is the root-mean-square voltage, $I_{rms}$ is the root-mean-square current, and $\cos\phi$ is the power factor of the circuit, with $\phi$ being the phase angle between voltage and current. \nWhen a circuit contains only a pure inductor ($L$) or a pure capacitor ($C$), the phase difference between the alternating voltage and alternating current is $\phi = \frac{\pi}{2}$ radians or $90^\circ$. \nSubstituting this into the power formula: $$\cos\left(\frac{\pi}{2}\right) = 0 \implies P = 0$$ \nThis means that even though current flows through the circuit, the average power consumed by the circuit over a full cycle is zero. This current, which flows without consuming any electrical energy, is called Wattless Current. \nIn general, the component of current $I_{rms} \sin\phi$ which is perpendicular to the voltage component in a phasor diagram is called the wattless component of current.

💡 Study Guide: This question tests core syllabus concepts from Alternating Current. For formulas, key summaries, and mock exam reference guides, read the full Alternating Current Revision Notes.
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