MP Board · Class 12 · Physics · Alternating CurrentThe ratio of peak value to the rms value of an alternating current is:
Step-by-Step Solution
Since $I_{rms} = \frac{I_0}{\sqrt{2}}$, the ratio of peak value ($I_0$) to rms value ($I_{rms}$) is $\frac{I_0}{I_{rms}} = \sqrt{2} : 1$.
Detailed Options Breakdown
Option : $1 : \sqrt{2}$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Alternating Current.
Option 1: $\sqrt{2} : 1$ (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: $1 : 2$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Alternating Current.
Option 3: $2 : 1$
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Alternating Current.
💡 Study Guide: This question tests core syllabus concepts from Alternating Current. For formulas, key summaries, and mock exam reference guides, read the full Alternating Current Revision Notes.