MP Board · Class 11 · Mathematics · Trigonometric FunctionsThe value of $\sin 75^{\circ}$ is:
We can write $\sin(75^{\circ}) = \sin(45^{\circ} + 30^{\circ})$. Using the formula $\sin(A + B) = \sin A \cos B + \cos A \sin B$, we get $\sin(45^{\circ})\cos(30^{\circ}) + \cos(45^{\circ})\sin(30^{\circ}) = \left(\frac{1}{\sqrt{2}}\right)\left(\frac{\sqrt{3}}{2}\right) + \left(\frac{1}{\sqrt{2}}\right)\left(\frac{1}{2}\right) = \frac{\sqrt{3} + 1}{2\sqrt{2}} = \frac{\sqrt{6} + \sqrt{2}}{4}$.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Trigonometric Functions.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Trigonometric Functions.
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Trigonometric Functions.