MP Board · Class 11 · Mathematics · Trigonometric FunctionsWhat is the value of $\sin\left(-\frac{11\pi}{3}\right)$?
We know that $\sin(-\theta) = -\sin(\theta)$. So, $\sin\left(-\frac{11\pi}{3}\right) = -\sin\left(\frac{11\pi}{3}\right)$. We can write $\frac{11\pi}{3} = 4\pi - \frac{\pi}{3}$. Thus, $-\sin\left(4\pi - \frac{\pi}{3}\right) = -\left(-\sin\left(\frac{\pi}{3}\right)\right) = \sin\left(\frac{\pi}{3}\right) = \frac{\sqrt{3}}{2}$.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Trigonometric Functions.
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Trigonometric Functions.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Trigonometric Functions.