MP Board · Class 10 · Mathematics · Introduction to TrigonometryIf $\tan 2A = \cot(A - 18^\circ)$, where $2A$ is an acute angle, then the value of $A$ is:
We know that $\tan 2A = \cot(90^\circ - 2A)$. Given equation is $\tan 2A = \cot(A - 18^\circ)$. Equating the angles, we get $90^\circ - 2A = A - 18^\circ$. Rearranging terms: $90^\circ + 18^\circ = 2A + A$, which gives $3A = 108^\circ$. Therefore, $A = \frac{108^\circ}{3} = 36^\circ$.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Introduction to Trigonometry.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Introduction to Trigonometry.
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Introduction to Trigonometry.