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MP Board · Class 10 · Mathematics · Introduction to TrigonometryWhat is the value of $\sin 30^\circ \cos 60^\circ + \cos 30^\circ \sin 60^\circ$?

Step-by-Step Solution

Using the trigonometric table values: $\sin 30^\circ = \frac{1}{2}$, $\cos 60^\circ = \frac{1}{2}$, $\cos 30^\circ = \frac{\sqrt{3}}{2}$, and $\sin 60^\circ = \frac{\sqrt{3}}{2}$. Substituting these values into the expression gives: $(\frac{1}{2} \times \frac{1}{2}) + (\frac{\sqrt{3}}{2} \times \frac{\sqrt{3}}{2}) = \frac{1}{4} + \frac{3}{4} = \frac{4}{4} = 1$. Alternatively, using the identity $\sin(A+B) = \sin A \cos B + \cos A \sin B$, we get $\sin(30^\circ + 60^\circ) = \sin 90^\circ = 1$.

Detailed Options Breakdown
Option : 0

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Introduction to Trigonometry.

Option 1: 1 (Correct Answer)

Correct choice. Refer to the step-by-step verified solution guidelines above for details.

Option 2: 1/2

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Introduction to Trigonometry.

Option 3: $\sqrt{3}$

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Introduction to Trigonometry.

💡 Study Guide: This question tests core syllabus concepts from Introduction to Trigonometry. For formulas, key summaries, and mock exam reference guides, read the full Introduction to Trigonometry Revision Notes.
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