MCQMathematics

MP Board · Class 10 · Mathematics · Applications of TrigonometryA kite is flying at a height of 60 m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 60°. Find the length of the string, assuming that there is no slack in the string.

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Step-by-Step Solution

Let the length of the string be $l$ m. The height of the kite is $60$ m. The angle of inclination is $60^\circ$. Therefore, $\sin 60^\circ = \frac{\text{Height}}{\text{Length of string}} = \frac{60}{l}$. Since $\sin 60^\circ = \frac{\sqrt{3}}{2}$, we have $\frac{\sqrt{3}}{2} = \frac{60}{l}$, which gives $l = \frac{120}{\sqrt{3}} = \frac{120\sqrt{3}}{3} = 40\sqrt{3}$ m.

Detailed Options Breakdown
Option : 20\sqrt{3} m

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.

Option 1: 40\sqrt{3} m (Correct Answer)

Correct choice. Refer to the step-by-step verified solution guidelines above for details.

Option 2: 60\sqrt{3} m

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.

Option 3: 80 m

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.

💡 Study Guide: This question tests core syllabus concepts from Applications of Trigonometry. For formulas, key summaries, and mock exam reference guides, read the full Applications of Trigonometry Revision Notes.
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