MP Board · Class 10 · Mathematics · Applications of TrigonometryA kite is flying at a height of 60 m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 60°. Find the length of the string, assuming that there is no slack in the string.
Let the length of the string be $l$ m. The height of the kite is $60$ m. The angle of inclination is $60^\circ$. Therefore, $\sin 60^\circ = \frac{\text{Height}}{\text{Length of string}} = \frac{60}{l}$. Since $\sin 60^\circ = \frac{\sqrt{3}}{2}$, we have $\frac{\sqrt{3}}{2} = \frac{60}{l}$, which gives $l = \frac{120}{\sqrt{3}} = \frac{120\sqrt{3}}{3} = 40\sqrt{3}$ m.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.