MP Board · Class 10 · Mathematics · Applications of TrigonometryThe angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. The height of the tower is:
Let the height of the tower be $h$ m. The distance from the foot of the tower is $30$ m. In the right-angled triangle, $\tan 30^\circ = \frac{\text{Height}}{\text{Base}} = \frac{h}{30}$. Since $\tan 30^\circ = \frac{1}{\sqrt{3}}$, we get $\frac{1}{\sqrt{3}} = \frac{h}{30}$, which implies $h = \frac{30}{\sqrt{3}} = 10\sqrt{3}$ m. Therefore, the correct option is $10\sqrt{3}$ m.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.