MP Board · Class 10 · Mathematics · Applications of TrigonometryA tower is 50 m high. What is the angle of elevation of its top from a point 50 m away from its foot on the ground?
Step-by-Step Solution
Let the angle of elevation be $\theta$. The height of the tower is $50$ m and the distance from the foot is $50$ m. Therefore, $\tan \theta = \frac{\text{Height}}{\text{Distance}} = \frac{50}{50} = 1$. Since $\tan 45^\circ = 1$, we get $\theta = 45^\circ$.
Detailed Options Breakdown
Option : 30°
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.
Option 1: 45° (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: 60°
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.
Option 3: 90°
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Applications of Trigonometry.
💡 Study Guide: This question tests core syllabus concepts from Applications of Trigonometry. For formulas, key summaries, and mock exam reference guides, read the full Applications of Trigonometry Revision Notes.