CBSE · Class 12 · Physics · Dual Nature of Radiation and MatterThe de Broglie wavelength of an electron accelerated through a potential difference of $100 \text{ V}$ is approximately:
Step-by-Step Solution
The formula for the de Broglie wavelength of an electron accelerated through potential $V$ is $\lambda = \frac{12.27}{\sqrt{V}} \text{ Å}$. For $V = 100 \text{ V}$, $\lambda = \frac{12.27}{\sqrt{100}} = \frac{12.27}{10} = 1.227 \text{ Å}$ or $0.123 \text{ nm}$.
Detailed Options Breakdown
Option : 1.23 Å (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: 12.3 Å
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Dual Nature of Radiation and Matter.
Option 2: 0.12 Å
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Dual Nature of Radiation and Matter.
Option 3: 123 Å
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Dual Nature of Radiation and Matter.
💡 Study Guide: This question tests core syllabus concepts from Dual Nature of Radiation and Matter. For formulas, key summaries, and mock exam reference guides, read the full Dual Nature of Radiation and Matter Revision Notes.