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CBSE · Class 12 · Physics · Dual Nature of Radiation and MatterWhich of the following particles has the shortest de Broglie wavelength for a given kinetic energy?

Step-by-Step Solution

The de Broglie wavelength is given by $\lambda = \frac{h}{p} = \frac{h}{\sqrt{2mK}}$, where $m$ is the mass and $K$ is the kinetic energy. For a given kinetic energy, wavelength is inversely proportional to the square root of the mass ($\lambda \propto \frac{1}{\sqrt{m}}$). Among the given options, the alpha particle has the maximum mass, hence it has the shortest de Broglie wavelength.

Detailed Options Breakdown
Option : Electron

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Dual Nature of Radiation and Matter.

Option 1: Proton

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Dual Nature of Radiation and Matter.

Option 2: Neutron

Incorrect choice. This distractor represents a common misunderstanding of the core principles of Dual Nature of Radiation and Matter.

Option 3: Alpha particle (Correct Answer)

Correct choice. Refer to the step-by-step verified solution guidelines above for details.

💡 Study Guide: This question tests core syllabus concepts from Dual Nature of Radiation and Matter. For formulas, key summaries, and mock exam reference guides, read the full Dual Nature of Radiation and Matter Revision Notes.
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