NCERT · Class 8 · Mathematics · Square and Square RootsWhich of the following is a Pythagorean triplet whose smallest member is 6?
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Total Attempts: 5
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Step-by-Step Solution
A Pythagorean triplet is of the form $(2m, m^2 - 1, m^2 + 1)$. \nGiven smallest member $2m = 6 \implies m = 3$.
- Second member: $m^2 - 1 = 3^2 - 1 = 8$
- Third member: $m^2 + 1 = 3^2 + 1 = 10$ \nThus, the triplet is (6, 8, 10).
Detailed Options Breakdown
Option : (6, 8, 10) (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: (6, 7, 8)
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Square and Square Roots.
Option 2: (6, 9, 12)
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Square and Square Roots.
Option 3: (6, 10, 14)
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Square and Square Roots.
💡 Study Guide: This question tests core syllabus concepts from Square and Square Roots. For formulas, key summaries, and mock exam reference guides, read the full Square and Square Roots Revision Notes.