NCERT · Class 8 · Mathematics · Cube and Cube RootsBy what smallest natural number should 256 be multiplied to make it a perfect cube?
Step-by-Step Solution
Prime factorization of $256 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 2^8$. To make triplets of 2, we need one more 2 ($2^8 \times 2 = 2^9 = 512 = 8^3$). Hence, the required smallest number is 2.
Detailed Options Breakdown
Option : 2 (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 1: 4
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Cube and Cube Roots.
Option 2: 3
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Cube and Cube Roots.
Option 3: 5
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Cube and Cube Roots.
💡 Study Guide: This question tests core syllabus concepts from Cube and Cube Roots. For formulas, key summaries, and mock exam reference guides, read the full Cube and Cube Roots Revision Notes.