NCERT · Class 12 · Physics · Moving Charges and MagnetismThe force per unit length between two parallel long straight conductors carrying currents $I1$ and $I2$ separated by a distance $d$ is:
Step-by-Step Solution
The magnetic force per unit length between two parallel conductors carrying currents $I_1$ and $I_2$ separated by distance $d$ is given by $F/L = \frac{\mu_0 I_1 I_2}{2 \pi d}$.
Detailed Options Breakdown
Option : mu_0 I_1 I_2 / (4 pi d)
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Moving Charges and Magnetism.
Option 1: mu_0 I_1 I_2 / (2 pi d) (Correct Answer)
Correct choice. Refer to the step-by-step verified solution guidelines above for details.
Option 2: mu_0 I_1 I_2 / (2 pi d^2)
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Moving Charges and Magnetism.
Option 3: 2 mu_0 I_1 I_2 / (pi d)
Incorrect choice. This distractor represents a common misunderstanding of the core principles of Moving Charges and Magnetism.
💡 Study Guide: This question tests core syllabus concepts from Moving Charges and Magnetism. For formulas, key summaries, and mock exam reference guides, read the full Moving Charges and Magnetism Revision Notes.